2026 H2 Timed Practice Paper 1 MCQ Combined + answer (finalised)

1 NJC SH2 Timed Practice 9476/1/26 [Turn over NATIONAL JUNIOR COLLEGE SH2 TIMED PRACTICE Higher 2 CANDIDATE NAME SUBJECT CLASS REGISTRATION NUMBER CHEMISTRY Paper A Multiple Choice Additional Materials: Optical Answer Sheet Data Booklet 9476/01 16 July 2026 1 hour READ THESE INSTRUCTIONS FIRST Write in soft pencil. Do not use staples, paper clips, glue or correction fluid. Write your name, subject class and registration number on the Answer Sheet in the spaces provided unless this has been done for you. There are thirty questions on this paper. Answer all questions. For each question there are four possible answers A, B, C and D. Choose the one you consider correct and record your choice in soft pencil on the separate Answer Sheet. Read the instructions on the Answer Sheet very carefully. Each correct answer will score one mark. A mark will not be deducted for a wrong answer. Any rough working should be done in this booklet. The use of an approved scientific calculator is expected, where appropriate. A Data Booklet is provided. Instructions on how to fill in the Optical Mark Sheet Shade the index number in a 5 digit format on the optical mark sheet: 2nd digit and the last 4 digits of the Registration Number. Example: Student Examples of Registration No. Shade: 2505648 55648 This document consists of 14 printed pages.

2 NJC SH2 Timed Practice 9476/1/26 1 Use of the Data Booklet is relevant to this question. Which sample of gas contains twice the number of atoms as 4 g of helium gas, He? A 4 g of hydrogen, H2 B 8 g of methane, CH4 C 12 g of steam, H2O D 22 g of carbon dioxide, CO2 Answer: C Molar mass / g mol⁻¹ Moles No. of atoms per molecule total moles of atoms 4 g of He 4 4 4 = 1 1 1 Twice the no.of He atoms = 2 moles of atoms. A. 4 g H₂ 2 4 2 = 2 2 2 × 2 = 4 ❌ B. 8 g CH₄ 15 8 16 = 0.5 5 0.5 × 5 = 2.5 ❌ C. 12 g H₂O 18 12 18 = 2 3 3 2 3 × 3 = 2 ✅ D. 22 g CO₂ 12 + 32 = 44 22 44 = 0.5 3 0.5 × 3 = 1.5 ❌

3 NJC SH2 Timed Practice 9476/1/26 [Turn over 2 The isotope of an element has a nucleon number of 112. It forms an ion with a charge of +2 with the electron configuration [Kr]4𝑑10. How many protons, neutrons, and electrons are present in this ion? A 46 protons, 66 neutrons, 44 electrons B 46 protons, 66 neutrons, 46 electrons C 48 protons, 64 neutrons, 46 electrons D 48 protons, 64 neutrons, 44 electrons Answer: C [Kr] = 36 electrons, plus 4𝑑10 = 10 electrons → ion has 46 electrons. • Charge +2 → neutral atom has 48 electrons → atomic number (proton no.) 48 (cadmium). • Nucleon number 112 → neutrons = 112 − 48 = 64. • Ion electrons = 46 (as above). 3 An element R consists of four isotopes. The table below shows the percentage abunda